TypeScript · Junior · Question 51 of 75

What does the `noImplicitAny` option report?

function greet(name) {
  return 'Hi ' + name;
}

✓Correct answer: Parameters and variables whose type would silently become any because nothing could be inferred
2Every use of the any keyword
3Functions without a return statement

Explanation

Here name would be any. The flag is part of strict. Writing any explicitly is still allowed, but it's a visible decision.

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