Angular · Junior · Question 50 of 75

What does `pipe(map(...), filter(...))` do on an Observable?

✓Correct answer: Composes operators that transform the stream and returns a new Observable
2Sends the stream to a server
3Subscribes to the Observable immediately

Explanation

Operators are pure functions: users$.pipe(map((list) => list.filter((u) => u.active))) returns a new Observable without changing the source and without subscribing.

What does `pipe(map(...), filter(...))` do on an Observable?

Explanation

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What does pipe(map(...), filter(...)) do on an Observable?

Explanation

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What does `pipe(map(...), filter(...))` do on an Observable?